69. Sqrt(x)

https://leetcode.com/problems/sqrtx/

JavaScript

/**
 * @param {number} x
 * @return {number}
 */
var mySqrt = function(x) {
  var i = 0
  var j = (x / 2 >> 0) + 1

  while (i <= j) {
    let mid = (i + j) / 2 >> 0
    if (mid * mid === x) {
      return mid
    } else if (mid * mid < x) {
      i = mid + 1
    } else {
      j = mid - 1
    }
  }

  return j
}

Python

class Solution(object):

    def mySqrt(self, x):
        """
        :type x: int
        :rtype: int
        """
        i, j = 0, x // 2 + 1
        while i <= j:
            mid = (i + j) // 2
            if mid * mid == x:
                return mid
            elif mid * mid < x:
                i = mid + 1
            else:
                j = mid - 1
        return j